Q.How do I show numbers with 5 fixed digits with leading zeroes
Ans:
int _num1 = 123;
int _num2 = 45;
int _num3 = 123456;
String.Format(”{0:00000}”, _num1); //”00123″
String.Format(”{0:00000}”, _num2); //”00045″
String.Format(”{0:00000}”, _num3); //”123456″
String.Format(”{0:d5}”, _num1); //”00123″
String.Format(”{0:d5}”, _num2); //”00045″
String.Format(”{0:d5}”, _num3); //”123456″
Q:Can I substitute a string for a value?
Ans:
Yes:
String.Format(”{0:yes;;no}”, value)
This will print “no” if value is 0, “yes” if value is 1.
Q:What’s the most efficient way to convert a type into a string?
Ans:
Double testDouble = 19.95;
String testString1 = String.Format(”{0:C}”, testDouble); // Boxing operation required.
String testString2 = testDouble.ToString(”C”); // No boxing operation required.
Q:How can I use curly brackets within a formatted number?
Ans:
Yes - doubling them escapes them. For example:
string.format(”{{SomeString}}={0}”,”Hello”);
will produce: “{SomeString}=Hellow”
Q:How can I convert from currency back to a number?
Ans:
You can add the bitmapped values of the Globalization.NumberStyles enumeration.
// format double to currency
str = string.Format(”{0:c}”, pmt);
// parse currency formatted string to double
double.Parse(str, Globalization.NumberStyles.AllowCurrencySymbol +
Globalization.NumberStyles.AllowDecimalPoint +
Globalization.NumberStyles.AllowThousands);
Q:What’s a good way to format currency?
Ans:
double val = 4219.6;
str = string.Format(”{0:$#,#.00;Call Us;Call Us}”, val);
This will return “$4,219.60″. The .00 will force 2 decimals and the “;Call Us;Call Us” to show the text “Call Us” in place of negative and null values respectively. (Just in case)
Q:How do I format an integer, with commas for thousands?
A:
string str = string.Format(”{0:#,0}”, intValue);
Q:How can I format a phone number to look like 800.555.1212?
A:
There’s no direct way to do this; however you can get dashes in the output. So you can do this:
string tempStr = String.Format(”{0:###-###-####}”, 8005551212);
string result =tempStr.Replace(’-’,’.’);